Persist object with JPA
With this example we are going to demonstrate how to persist an object using the JPA. The Java Persistence API provides Java developers with an object/relational mapping facility for managing relational data in Java applications.
Here, we are using JPA to persist an object, as shown below:
The PersistObjectWithJPA class
In PersistObjectWithJPA
class we create an EntityManagerFactory
interface to interact with the entity manager factory for MyPeristenceUnit
, that is defined in persistence.xml
file. We create an EntityManager, using the createEntityManager()
API method. Then, we create a new ProjectManager
object. The new object is writen to the database, using the persist(java.lang.Object entity)
API method of EntityManager
. The getTransaction().begin()
and getTransaction().commit()
methods are used before and after the EntityManager
invokes a method so that a transaction begins and ends.
package com.javacodegeeks.snippets.enterprise; import java.util.Date; import javax.persistence.EntityManager; import javax.persistence.EntityManagerFactory; import javax.persistence.Persistence; public class PersistObjectWithJPA { public static void main(String[] args) { EntityManagerFactory emf = Persistence.createEntityManagerFactory("MyPersistenceUnit"); EntityManager em = emf.createEntityManager(); em.getTransaction().begin(); Employee employee = new Employee(); employee.setName("Jack"); employee.setSurname("Thomson"); employee.setTitle("QA Engineer"); employee.setCreated(new Date()); em.persist(employee); em.getTransaction().commit(); em.close(); emf.close(); } }
Employee Class
The Employee
class is an entity class, annotated with the javax.persistence.Entity
annotation. It uses the @Id
annotation to define its id property, and the @GeneratedValue
annotation with strategy set to GenerationType.AUTO
so that the id gets auto-generated values.
package com.javacodegeeks.snippets.enterprise; import java.util.Date; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; @Entity public class Employee { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; private String name; private String surname; private String title; private Date created; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getSurname() { return surname; } public void setSurname(String surname) { this.surname = surname; } public String getTitle() { return title; } public void setTitle(String title) { this.title = title; } public Date getCreated() { return created; } public void setCreated(Date created) { this.created = created; } @Override public String toString() { return "Employee [id=" + id + ", name=" + name + ", surname=" + surname + ", title=" + title + "]"; } }
persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0"> <persistence-unit name="MyPersistenceUnit" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect" /> <property name="hibernate.hbm2ddl.auto" value="update" /> <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" /> <property name="hibernate.connection.username" value="jcg" /> <property name="hibernate.connection.password" value="jcg" /> <property name="hibernate.connection.url" value="jdbc:mysql://localhost/companydb" /> </properties> </persistence-unit> </persistence>
This was an example of how to persist an object using the JPA.