List contents of zip file

In this example we shall show you how to get the list of the contents of a zip file, with ZipFile that is used to read entries from a zip file. To get the files that a zip file contains one should perform the following steps:

  • Create a new ZipFile and open it for reading.
  • Get the Enumeration of the ZipFile entries, with entries() API method of ZipFile and iterate through each one of them.
  • For each one of the entries, get its name, with getName() API method of ZipEntry.
  • Close the ZipFile, with close() API method of ZipFile,
  • as described in the code snippet below.

package com.javacodegeeks.snippets.core;

import java.util.Enumeration;

public class ListContentsOfZipFile {
	public static void main(String[] args) {
		ZipFile zipFile = null;

		try {
			// open a zip file for reading
			zipFile = new ZipFile("c:/");

			// get an enumeration of the ZIP file entries
			Enumeration<? extends ZipEntry> e = zipFile.entries();

			while (e.hasMoreElements()) {
				ZipEntry entry = e.nextElement();

				// get the name of the entry
				String entryName = entry.getName();
				System.out.println("ZIP Entry: " + entryName);


		catch (IOException ioe) {
			System.out.println("Error opening zip file" + ioe);
		 finally {
			 try {
				 if (zipFile!=null) {
			 catch (IOException ioe) {
					System.out.println("Error while closing zip file" + ioe);


This was an example of how to get the list of the contents of a zip file in Java.

Ilias Tsagklis

Ilias is a software developer turned online entrepreneur. He is co-founder and Executive Editor at Java Code Geeks.
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