Matcher start example

In this example we shall show you how to use Matcher.start() API method to get the start index of the previous match of a sequence against a pattern. To use Matcher.start() one should perform the following steps:

  • Compile a String regular expression to a Pattern, using compile(String regex) API method of Pattern.
  • Use an initial String to be matched against the Pattern.
  • Use matcher(CharSequence input) API method of Pattern to create a Matcher that will match the given String input against this pattern.
  • Find the next subsequence of the input sequence that matches the pattern it returns it, using find() API method of Matcher.
  • Get the start index of the first match, with start() API method of Matcher.
  • Find the next subsequence, and again the start index of the second match.

Let’s take a look at the code snippet that follows:

package com.javacodegeeks.snippets.core;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MatcherStart {

    public static void main(String args[]) {


  String str = "My name is Bond. James Bond.";

  String mHelp[] = {"
    ^", "


  Pattern pattern = Pattern.compile("Bond");

  Matcher m = pattern.matcher(str);

  //Find the starting point of the first 'Bond'


  int sIndex = m.start();


  System.out.println(mHelp[0] + sIndex);

  //Find the starting point of the second 'Bond'


  int nIndex = m.start();


  System.out.println(mHelp[1] + nIndex);



My name is Bond. James Bond.

My name is Bond. James Bond.


This was an example of Matcher.start() API method in Java.

Byron Kiourtzoglou

Byron is a master software engineer working in the IT and Telecom domains. He is an applications developer in a wide variety of applications/services. He is currently acting as the team leader and technical architect for a proprietary service creation and integration platform for both the IT and Telecom industries in addition to a in-house big data real-time analytics solution. He is always fascinated by SOA, middleware services and mobile development. Byron is co-founder and Executive Editor at Java Code Geeks.
Notify of

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Inline Feedbacks
View all comments
Back to top button