Home » Core Java » math » Find natural logarithm value of a number Byron is a master software engineer working in the IT and Telecom domains. He is an applications developer in a wide variety of applications/services. He is currently acting as the team leader and technical architect for a proprietary service creation and integration platform for both the IT and Telecom industries in addition to a in-house big data real-time analytics solution. He is always fascinated by SOA, middleware services and mobile development. Byron is co-founder and Executive Editor at Java Code Geeks.

# Find natural logarithm value of a number

This is an example of how to find the natural logarithm value of a number, using the `log(double a)` method of Math. The class Math contains methods for performing basic numeric operations such as the elementary exponential, logarithm, square root, and trigonometric functions. Finding the natural logarithm value of a number implies that you should:

• Use `log(double a)` API method of Math. The method returns the natural logarithm (base e) of a double value.

Let’s take a look at the code snippet that follows:

```package com.javacodegeeks.snippets.core;

public class NatularLogarithmValue {

public static void main(String args[]) {

System.out.println("Natural logarithm value of 1 is : " + Math.log(1));
System.out.println("Natural logarithm value of 2 is : " + Math.log(2));

}
}```

Output:

``Natural logarithm value of 1 is : 0.0 Natural logarithm value of 2 is : 0.6931471805599453``

This was an example of how to find the natural logarithm value of a number in Java.

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