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About Byron Kiourtzoglou

Byron Kiourtzoglou
Byron is a master software engineer working in the IT and Telecom domains. He is an applications developer in a wide variety of applications/services. He is currently acting as the team leader and technical architect for a proprietary service creation and integration platform for both the IT and Telecom industries in addition to a in-house big data real-time analytics solution. He is always fascinated by SOA, middleware services and mobile development. Byron is co-founder and Executive Editor at Java Code Geeks.

List directory contents

With this example we are going to demonstrate how to list the contents of a directory, using the list() API method of File. In short, to list all contents that a directory contains you should:

  • Create a new File instance by converting the given pathname string into an abstract pathname.
  • Use list() API method of File. This method returns an array of strings naming the files and directories in the directory denoted by this abstract pathname.

Let’s take a look at the code snippet that follows:

package com.javacodegeeks.snippets.core;

import java.io.File;

public class ListDirectoryContents {
	public static void main(String[] args) {
		File dir = new File("C://directory");
		String[] files = dir.list();

		System.out.println("Listing contents of directory: " + dir.getPath());
		for (int i = 0; i < files.length; i++) {
			System.out.println("File/Dir found: " + files[i]);

This was an example of how to list the contents of a directory in Java.

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