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About Aldo Ziflaj

Aldo Ziflaj
Aldo is a student of Computer Engineering and a programming addict. He spares his free time coding, whether mobile, web, or desktop programming. He is also one of the co-founders of Things Lab.

Java equals method Example

In this example we will discuss about equals() method. This is one of the methods that all objects have, since it is defined in the Object class, which is the base for all Java classes.

This method’s functionality is to check if the object invoking this method is equal to another object passed as an argument. It should return true if the objects are equal, otherwise it should return false.

It is generally necessary to override the hashCode() method whenever the equals() method is overridden, so as to maintain the general contract for the hashCode() method, which states that equal objects must have equal hash codes.

The equals() method for the Object class implements the most discriminating possible equivalence relation on objects; that is, for any non-null reference values x and y, this method returns true if and only if x and y refer to the same object (x == y has the value true).

Example of equals() usage

In this example, I will show that for two references x and y, when x == y is true, also x.equals(y) is true, but the opposite is not always true.
Create a class called BasicEqualsExample with the following source code:

package com.javacodegeeks.example;

public class BasicEqualsExample {

	public static void main(String[] args) {
		String s1 = new String("John");
		String s2 = new String("John");
		String s3 = s1; //references of the same object
		System.out.println("s1 == s2: "+(s1 == s2));
		System.out.println("s1.equals(s2): "+(s1.equals(s2)));
		System.out.println("s1 == s3: "+(s1 == s3));
		System.out.println("s1.equals(s3): "+(s1.equals(s3)));



On this example, I created 3 new instances of the String class. Two of them are references to the same object, (s1 and s3), while two others have the same content, but are different objects (s1 and s2).
As you can see, the == operator returns true only when the objects refer to the same address in the memory, without checking the content of the memory. On the other hand, the equals() method doesn’t care about the memory address; it checks the values of the objects, not their references.
The output, is this:

s1 == s2: false
s1.equals(s2): true
s1 == s3: true
s1.equals(s3): true

Implementing the equals() method

To show a basic implementation of the equals() method, I will firstly create a new class, called Vehicle, with the following source code:

package com.javacodegeeks.example.impl;

public class Vehicle {
	private String model;
	private int yearOfProduction;
	private String manufacturer;
	public Vehicle() {}
	public Vehicle(String model, int yearOfProduction, String manufacturer) {
		this.model = model;
		this.yearOfProduction = yearOfProduction;
		this.manufacturer = manufacturer;
	public boolean equals(Vehicle v) {
		if (v == null) return false;
		return ((this.model).equals(v.model)
				&& (this.yearOfProduction == v.yearOfProduction)
				&& (this.manufacturer).equals(v.manufacturer));


You can see the implementation of the equals() method there, but to see it in action, I created another class, called Main, with this source code:

package com.javacodegeeks.example.impl;

public class Main {

	public static void main(String[] args) {
		Vehicle myCar = new Vehicle("Focus",2002,"Ford");
		Vehicle minivan = new Vehicle ("Odyssey",2014,"Honda");
		Vehicle focus = new Vehicle("Focus",2002,"Ford");
		if (myCar.equals(minivan)) {
			System.out.println("This isn't supposed to print!");
		if (myCar.equals(focus)) {
			System.out.println("The equals method is implemented OK");



As you expected, the output will be this:

The equals method is implemented OK

More about equals() method

The equals method implements an equivalence relation on non-null object references:

  • It is reflexive: for any non-null reference value x, x.equals(x) should return true.
  • It is symmetric: for any non-null reference values x and y, x.equals(y) should return true if and only if y.equals(x) returns true.
  • It is transitive: for any non-null reference values x, y, and z, if x.equals(y) returns true and y.equals(z) returns true, then x.equals(z) should return true.
  • It is consistent: for any non-null reference values x and y, multiple invocations of x.equals(y) consistently return true or consistently return false, provided no information used in equals comparisons on the objects is modified.
  • For any non-null reference value x, x.equals(null) should return false.

Now, I will test my equals() implementation against all of the above:

package com.javacodegeeks.example.impl;

public class VehicleTest {
	public static void main(String[] args) {
		Vehicle x = new Vehicle("Focus",2002,"Ford");
		Vehicle y = new Vehicle("Focus",2002,"Ford");
		Vehicle z = new Vehicle("Focus",2002,"Ford");
		int correctCases = 0;

		//reflexiveness test
		if (x.equals(x)) {
			System.out.println("It is reflexive!");
		} else {
			System.out.println("It is not reflexive");
		//symmetry test
		if (x.equals(y) && y.equals(x)) {
			System.out.println("It is symmetric!");
		} else {
			System.out.println("It is not symmetric");
		//transitiveness test
		boolean cause1 = x.equals(y) && y.equals(z);
		if (cause1 == x.equals(z)) {
			System.out.println("It is transitive!");
		} else {
			System.out.println("It is not transitive");
		if (x.equals(null) == false) {
			System.out.println("Nothing equals null");
		} else {
			System.out.println("An object equals null?!");
		System.out.println(correctCases+"/4 correct cases");


Fortunately, my method is correctly implemented, and the output is this:

It is reflexive!
It is symmetric!
It is transitive!
Nothing equals null
4/4 correct cases

I didn’t test for the consistency of the method, because it is actually obvious: if the properties of x and y objects don’t change, the equals() method will return the same value.

Download Code

You can download the full source code of this example here : EqualsExample

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