This is an example of how to compare File objects using the hashcode. Each class in Java inherits hashCode() method from Object class. Comparing File objects using the hashcode implies that you should:
- Create a few new File instances, by converting the given pathname strings into abstract pathnames.
- For each one of the files, use
hashCode()API method of File. The method computes a hash code for each abstract pathname. Because equality of abstract pathnames is inherently system-dependent, so is the computation of their hash codes.
Let’s take a look at the code snippet that follows:
package methodoverloading;
import java.io.File;
public class Main {
public static void main(String[] argv) throws Exception {
File file1 = new File("f1");
File file2 = new File("f2");
File file3 = new File("f3");
int hc1 = file1.hashCode();
System.out.println(hc1);
int hc2 = file2.hashCode();
System.out.println(hc2);
int hc3 = file3.hashCode();
System.out.println(hc3);
}
}
Output:
-1702042073
-1185803119
-1185149680
This was an example of how to compare File objects using the hashcode in Java.
if my file name both are different but content same now how I compare two files with the hash code?